I need help with this math problem?
回答 (6)
2020-05-12 10:18 pm
The shape is a trapezoid.
Area of the trapezoid
= (upper base + lower base) × height / 2
= (9 + 3) × 3 / 2
= 18 (sq. units)
Area of the trapezoid
= (upper base + lower base) × height / 2
= (9 + 3) × 3 / 2
= 18 (sq. units)
2020-05-12 10:15 pm
That's a trapezoid with two parallel bases (9 and 3) and a given height (3).
To find the area, first take the average of the bases,
(3 + 9)/2
= 12/2
= 6
Then multiply it by the height:
6 * 3
= 18 units²
Another way to see this is to draw another vertical line from the top base to the right-hand vertex on the bottom base.
You now have a square and two congruent triangles.
The square is 3 * 3 = 9 units²
And the two triangles can actually be put together to make another 3 by 3 square.
3 * 3 = 9 units²
That's a total of 18 units²
To find the area, first take the average of the bases,
(3 + 9)/2
= 12/2
= 6
Then multiply it by the height:
6 * 3
= 18 units²
Another way to see this is to draw another vertical line from the top base to the right-hand vertex on the bottom base.
You now have a square and two congruent triangles.
The square is 3 * 3 = 9 units²
And the two triangles can actually be put together to make another 3 by 3 square.
3 * 3 = 9 units²
That's a total of 18 units²
2020-05-12 10:17 pm
Explanation:
Let ABCDEF be the shape given.where BF is the dotted line (as shown). draw another line CE parallel to the dotted line BF. BC = EF=3 and AB = CD = (AD-BC)/2 = (9-3)/2 = 3Then BCEF becomes a square. Area(BCEF) = (BC*BF) = 3*3 = 9 unit^2Triangle ABF and CDE are identical so the area are equal.Area(ABF) = (1/2)b*h = (1/2)*(EF)*BF = (1/2)*3*3 = 9/2 = 4.5 unit^2Total area = Area of AEF + area of BCEF + area of CDE= (4.5 + 9 + 4.5) unit^2 = 18 unit^2 <= ans
Let ABCDEF be the shape given.where BF is the dotted line (as shown). draw another line CE parallel to the dotted line BF. BC = EF=3 and AB = CD = (AD-BC)/2 = (9-3)/2 = 3Then BCEF becomes a square. Area(BCEF) = (BC*BF) = 3*3 = 9 unit^2Triangle ABF and CDE are identical so the area are equal.Area(ABF) = (1/2)b*h = (1/2)*(EF)*BF = (1/2)*3*3 = 9/2 = 4.5 unit^2Total area = Area of AEF + area of BCEF + area of CDE= (4.5 + 9 + 4.5) unit^2 = 18 unit^2 <= ans
2020-05-12 9:41 pm
The area of the given shape is 18 units^2.
2020-05-12 9:30 pm
The area of the shape is below the instructions, in purple. I hope this helps.
2020-05-12 9:40 pm
The shape you see before you is a 'Trapezoid', whose area is determined by the formula:
A = 0.5(b1 + b2) / h
A = 0.5(3 + 9) / 3
A = 6 / 3
A = 2
Therefore, the area is 2
Answer:
2
2
2
2
2
2
2
2
A = 0.5(b1 + b2) / h
A = 0.5(3 + 9) / 3
A = 6 / 3
A = 2
Therefore, the area is 2
Answer:
2
2
2
2
2
2
2
2
收錄日期: 2021-04-24 07:49:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200512132536AA8AxzH