What is the mass in grams of solute in 26.0 ml of 0.150 M sucrose (342g/mole)?
回答 (2)
2020-05-06 2:20 pm
Moles of sucrose (solute) = (0.150 mol/L) × (26.0/1000 L) = 0.00390 mol
Mass of sucrose = (0.00390 mol) × (342 g/mol) = 1.33 g (to 3 sig. fig.)
Mass of sucrose = (0.00390 mol) × (342 g/mol) = 1.33 g (to 3 sig. fig.)
2020-05-06 1:35 pm
Hint: The moles = volume in L * concentration in M
收錄日期: 2021-04-12 12:52:38
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