Find the standard form for the equation of a circle
(x−h)2+(y−k)2=r2
with a diameter that has endpoints (−6,8) and (5,9).
h=
k=
r=
How to do this?
2020-05-05 10:46 pm
回答 (1)
2020-05-05 10:55 pm
Center of the circle
= ((-6+5)/2, (8+9)/2)
= (-1/2, 17/2)
Hence,
h = -1/2
k = 17/2
Radius, r
= √[(-6 - 5)² + (8 - 9)²]
= √[(-11)² + (-1)²]
= √(121 + 1)
= √122
Standard form of the equation of the circle:
[x - (-1/2)]² + [y - (17/2)²] = (√122)²
i.e. [x + (1/2)]² + [y - (17/2)²] = 122
= ((-6+5)/2, (8+9)/2)
= (-1/2, 17/2)
Hence,
h = -1/2
k = 17/2
Radius, r
= √[(-6 - 5)² + (8 - 9)²]
= √[(-11)² + (-1)²]
= √(121 + 1)
= √122
Standard form of the equation of the circle:
[x - (-1/2)]² + [y - (17/2)²] = (√122)²
i.e. [x + (1/2)]² + [y - (17/2)²] = 122
收錄日期: 2021-04-18 18:30:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200505144639AAOppMf