how many mL of ethanol would be required in 225 mL of water to make a 38% ethanol by volume solution?
回答 (2)
2020-05-05 9:27 pm
Let y mL be the volume of ethanol.
y / (y + 225) = 38/100
100y = 38 (y +225)
100y = 38y + 8550
62y = 8550
y = 138
Volume of ethanol = 138 mL
y / (y + 225) = 38/100
100y = 38 (y +225)
100y = 38y + 8550
62y = 8550
y = 138
Volume of ethanol = 138 mL
2020-05-05 9:31 pm
38% ethanol means that the solution is 38 parts ethanol to 62 parts water. (Notice that 38 + 62 = 100.) So each part is 225 mL / 62 = 3.629 mL. We need 38 of these parts, and 38 * 3.629 mL = 137.9 mL. We need 137.9 mL of ethanol.
收錄日期: 2021-04-18 18:28:47
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