Copper carbonate decomposes to form copper oxide solid and carbon dioxide gas.
CuCO3(s) rightwards arrowCuO(s) + CO2(g)
The results obtained are in Table 1 below:
Table 1: Results of decomposition
Mass of test tube
18.88 g
Mass of test tube + CuCO3
20.74 g
Mass of CuCO3
1.86 g
Mass of test tube + CuO (after heating)
19.96 g
The actual mass of CuO
a. From the results in the table, calculate the actual mass of CuO formed. [1 point]
b. Given that 1.86 g of CuCO3 is equal to 0.015 moles, use the reaction equation CuCO3(s) rightwards arrowCuO(s) + CO2(g) to calculate:
i. Number of moles of CuO formed [1 point]
ii. Mass of CuO formed [2 points]
iii. Hence find the percent yield [1 point]
determine the percent yield of copper oxide (CuO) in the decomposition of copper (II) carbonate(CuCO3). ?
2020-05-02 8:15 pm
回答 (2)
2020-05-02 9:05 pm
a.
Actual mass of CuO formed = (19.96 - 18.88) g = 1.08 g
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b. i.
CuCO₃ → CuO + CO₂
Mole ratio CuCO₃ : CuO = 1 : 1
Moles of CuO formed = Moles of CuCO₃ reacted = 0.015 mol
====
b. ii.
Molar mass of CuO = (64 + 16) = 80 g/mol
Mass of CuO formed = (0.015 mol) × (80 g/mol) = 1.2 g
====
c. iii.
Percent yield = (1.08/1.2) × 100% = 90%
Actual mass of CuO formed = (19.96 - 18.88) g = 1.08 g
====
b. i.
CuCO₃ → CuO + CO₂
Mole ratio CuCO₃ : CuO = 1 : 1
Moles of CuO formed = Moles of CuCO₃ reacted = 0.015 mol
====
b. ii.
Molar mass of CuO = (64 + 16) = 80 g/mol
Mass of CuO formed = (0.015 mol) × (80 g/mol) = 1.2 g
====
c. iii.
Percent yield = (1.08/1.2) × 100% = 90%
2020-05-02 9:03 pm
Copper II Carbonate → Copper Oxide + Carbon Dioxide
CuCO₃ → CuO + CO₂
1 mole of CuCO₃ → 1 mole of CuO + 1 mole of CO₂
123.6 g of CuCO₃ → 79.6 g of CuO + 44 g of CO₂
CuCO₃ → CuO + CO₂
1 mole of CuCO₃ → 1 mole of CuO + 1 mole of CO₂
123.6 g of CuCO₃ → 79.6 g of CuO + 44 g of CO₂
收錄日期: 2021-04-30 18:00:00
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