what would the x intercept of f be from f (x) = 1 - e^x?

y = f(x) = 1 - eˣ

When y = 0:
1 - eˣ = 0
eˣ = 1
x = ln(1)
x = 0

x-intercept of x = 0

The x - intercept is when y = 0
Hence let f(x) = y = 0
Hence 1 - e^x = 0
e^x = 1
Hence
e^0 = 1
Because any number raised to the power 'zero' equals '1'.

Hence
f(0) = 1 - e^(0) = 1 - 1 = 0 = y

f(x) = 1 - e^(x)

set f(x) = 0

 0 = 1 - e^(x) 
e^(x) = 1 
x = ln(1) 
x = 0 answer//

Therefore, the  x - intercept is (0,0)...//