Another chm question?

Cd₃(PO₄)₂(s) ⇌ 3Cd²⁺(aq) + 2PO₄³⁻(aq)    Ksp = 2.5 × 10⁻³³
Initial:                  0 M               0 M
Change:           +3s M           +2s M
Equilibrium:        3s M             2s M

At equilibrium:
Ksp = [Cd²⁺]³ [PO₄³⁻]²
2.5 × 10⁻³³ = (3s)³ (2s)²
108s⁵ = 2.5 × 10⁻³³
s = ⁵√(2.5 × 10⁻³³ / 108)
Solubility, s = 1.18 × 10⁷ M