if time of flight of a projectile is 4.1sec then find the Maximum height of projectile?
回答 (1)
2020-04-29 4:57 pm
Take g = 9.81 m/s²
Maximum height of the projectile
= (1/2) g t²
= (1/2) × 9.81 × 4.1² m
= 165 m
Maximum height of the projectile
= (1/2) g t²
= (1/2) × 9.81 × 4.1² m
= 165 m
2020-04-29 5:17 pm
By T = 2usinθ/g
=>usinθ = Tg/2 = [4.1 x 9.8]/2
=>usinθ = 20.09 ------------------(i)
As H = (usinθ)^2/2g
=>H = (20.09)^2/(2 x 9.8)
=>H = 20.59 m
=>usinθ = Tg/2 = [4.1 x 9.8]/2
=>usinθ = 20.09 ------------------(i)
As H = (usinθ)^2/2g
=>H = (20.09)^2/(2 x 9.8)
=>H = 20.59 m
收錄日期: 2021-04-18 18:27:38
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