what is the equilibrium constant for this reaction?
2020-04-24 10:32 pm
the following reaction: 2NOBr (g) <=> 2NO (g) + Br2 (g) reached equilibrium when the concentrations were: [NOBr] = 0.10 M, [NO] = 0.010 M, and [Br2] = 0.0050 M.
回答 (1)
2020-04-24 10:50 pm
2NOBr(g) ⇌ 2NO(g) + Br₂(g) Kc
Equilibrium constant, Kc
= [NO]² [Br₂] / [NOBr]²
= 0.010² × 0.0050 / 0.10²
= 5.0 × 10⁻⁵
Equilibrium constant, Kc
= [NO]² [Br₂] / [NOBr]²
= 0.010² × 0.0050 / 0.10²
= 5.0 × 10⁻⁵
收錄日期: 2021-04-18 18:28:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200424143200AAT04lF