Trigonometry?
回答 (5)
2020-04-20 11:22 am
1 - sec²x
————–
sec²x
1 sec²x
= ——— − ———
sec²x sec²x
= cos²x − 1 ← Apply Identity sin²x + cos²x = 1
= -sin²x
————–
sec²x
1 sec²x
= ——— − ———
sec²x sec²x
= cos²x − 1 ← Apply Identity sin²x + cos²x = 1
= -sin²x
2020-04-20 9:59 am
rules
secx = 1/cosx
sin^2x+cos^2x=1
secx = 1/cosx
sin^2x+cos^2x=1
2020-04-20 9:57 am
Steve................
2020-04-20 10:04 am
1 - sec^2 (x) / sec^2 (x)
= cos^2(x) (1 - sec^2(x))
= (cos(x) - 1) (cos(x) + 1)
= -sin^2(x)
= cos^2(x) (1 - sec^2(x))
= (cos(x) - 1) (cos(x) + 1)
= -sin^2(x)
收錄日期: 2021-04-23 23:06:16
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