How much energy, in calories, is released as 190g water is cooled from 55.0°C to 12.0°C?

2020-04-17 12:55 pm

回答 (2)

2020-04-17 1:00 pm
Energy released, E
= m c ΔT
= (190 g) × (1.00 cal/g°C) × [(55.0 - 12.0)°C]
= 8170 cal
2020-04-17 2:17 pm
E = m*c*(Tf-Ti ) = 190 g* 1 cal/(g*°C) * (12-55) = -8,170 cal 


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