If Oxygen gas occupies 40.0 mL at 100°C. What would the volume be at 50°C? ?
回答 (3)
2020-04-15 11:52 pm
Original: T₁ = (273 + 100) K = 373 K, V₁ = 40.0 mL
New: T₂ = (273 + 50) K = 323 K, V₂ = ? mL
For a fixed amount of gas at constant pressure: V₁/T₁ = V₂/T₂
Then, V₂ = V₁ × (T₂/T₁)
New volume, V₂ = 40.0 × (323/273) mL = 34.6 mL
New: T₂ = (273 + 50) K = 323 K, V₂ = ? mL
For a fixed amount of gas at constant pressure: V₁/T₁ = V₂/T₂
Then, V₂ = V₁ × (T₂/T₁)
New volume, V₂ = 40.0 × (323/273) mL = 34.6 mL
2020-04-16 12:07 am
(40.0 mL) x (50 + 273) K / (100 + 273) K = 34.6 mL
2020-04-15 11:48 pm
V1/T1 = V2/T2
Convert temperatures from deg C to K, substitute and solve for V2.
Convert temperatures from deg C to K, substitute and solve for V2.
收錄日期: 2021-04-18 18:27:57
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