225 sin theta cos theta =100. Simplify this.?
回答 (3)
2020-04-15 3:35 pm
225 sin(θ) cos(θ) = 100
225 × [2 sin(θ) cos(θ)] = 200
225 sin(2θ) = 200
sin(2θ) = 200/225
sin(2θ) = 8/9
225 × [2 sin(θ) cos(θ)] = 200
225 sin(2θ) = 200
sin(2θ) = 200/225
sin(2θ) = 8/9
2020-04-15 3:33 pm
225 sinΘ cosΘ = 100
sinΘ cosΘ = 100/225 = 4/9
sinΘ cosΘ = (1/2)sin(2Θ) = 4/9
sin(2Θ) = 8/9
sinΘ cosΘ = 100/225 = 4/9
sinΘ cosΘ = (1/2)sin(2Θ) = 4/9
sin(2Θ) = 8/9
2020-04-15 3:12 pm
Rule
2sin(x)cos(x) = sin(2x)
2sin(x)cos(x) = sin(2x)
收錄日期: 2021-05-01 22:35:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200415070934AA1bs2M