✔ 最佳答案
Let m - mass of boiling water to be added
specific heat capacity of water=4.2 J kg⁻¹ ⁰C⁻¹
heat lost by boiling water = heat gained by cold water + heat gained by cup
m×4.2×(100-40)=0.1×4.2×(40-10)+0.04×700×(40-10)
252m=12.6+840
∴ m=3.38 kg (to 2 dec.pl.)