What volume will 2.50 mol of a gas occupy at 283K and a pressure of 0.395 atm?
回答 (1)
2020-04-13 10:00 pm
No. of moles, n = 2.50 mol
Temperature, T = 283 K
Pressure, P = 0.395 atm
Gas constant, R = 0.08206 L atm / (mol K)
PV = nRT
Then, V = nRT/P
Volume, V = 2.50 × 0.08206 × 283 / 0.395 L = 147 L
Temperature, T = 283 K
Pressure, P = 0.395 atm
Gas constant, R = 0.08206 L atm / (mol K)
PV = nRT
Then, V = nRT/P
Volume, V = 2.50 × 0.08206 × 283 / 0.395 L = 147 L
收錄日期: 2021-04-18 18:26:18
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