The number of grams of (NH4)2SO4 needed to make 440.mL of a 2.75M solution is nearest to a. 363 b. 313 c. 160. d. 138 e. 58.0?
回答 (1)
2020-04-08 11:00 pm
✔ 最佳答案
Moles of (NH₄)₂SO₄ = (2.75 mol/L) × (440/1000 L) = 1.21 molMolar mass of (NH₄)₂SO₄ = 14.0×2 + 1.0×8 + 32.1 + 16.0×4 = 132.1 g/mol
Mass of (NH₄)₂SO₄ = (1.21 mol) × (132.1 g/mol) = 160. g
The answer: c. 160.
收錄日期: 2021-04-24 07:51:49
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