Find the distance between the two values of x at which the function 1/(x^2-4x+3) is discontinuous.
I have always struggled with this concept. Please explain to me how you solved it! Thank you so much!
I need help with my AP Calculus AB limits review!?
2020-04-08 12:48 pm
回答 (2)
2020-04-08 12:55 pm
✔ 最佳答案
f(x) = 1/(x² - 4x + 3)f(x) = 1/[(x - 1)(x - 3)]
f(x) is discontinuous when the denominator is equal to 0, i.e.
(x - 1)(x - 3) = 0
x = 1 or x = 3
Distance between the two values of x
= 3 - 1
= 2
2020-04-08 12:52 pm
x^2 -4x + 3 = (x-1)(x-3)
so function is discontinuous at x =1 and x = 3 Both require division by 0.
so function is discontinuous at x =1 and x = 3 Both require division by 0.
收錄日期: 2021-04-30 17:39:48
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