How can I solve this equation, 2sin^2 x+1=3sinx find all values in 0,360?
回答 (1)
2020-04-08 12:02 am
2 sin²(x) + 1 = 3 sin(x)
2 sin²(x) - 3 sin(x) + 1 = 0
[2 sin(x) - 1] [sin(x) - 1] = 0
sin(x) = 1/2 or sin(x) = 1
x = 30°, (180 - 30)° or x = 90°
x = 30°, 90°, 150°
2 sin²(x) - 3 sin(x) + 1 = 0
[2 sin(x) - 1] [sin(x) - 1] = 0
sin(x) = 1/2 or sin(x) = 1
x = 30°, (180 - 30)° or x = 90°
x = 30°, 90°, 150°
收錄日期: 2021-04-18 18:27:19
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https://hk.answers.yahoo.com/question/index?qid=20200407155035AAZX2DP