Polygon where one side is 110°, the others are 5x° and 2x°. How do I find x?
回答 (3)
2020-04-07 2:27 pm
Suppose "one side" is "one angle" instead.
As there are only three angles, the polygon is a triangle.
Sum of interior angles of a triangle = 180°
110° + 5x° + 2x° = 180°
7x = 70
x = 10
As there are only three angles, the polygon is a triangle.
Sum of interior angles of a triangle = 180°
110° + 5x° + 2x° = 180°
7x = 70
x = 10
2020-04-07 3:05 pm
If your polygon only has 3 angles, 110°, 5x° and 2x°, then your polygon is a TRIANGLE. All angles in a triangle sum to 180° so
110° + 5x° + 2x° = 180°
7x° = 70°
x = 10°...............ANS
// And your angles are 110°, 50° and 20°
110° + 5x° + 2x° = 180°
7x° = 70°
x = 10°...............ANS
// And your angles are 110°, 50° and 20°
2020-04-07 6:45 pm
110 + 5x + 2x = 180
110 + 7x = 180
7x = 180 - 110
7x = 70
x = 10 answer//
then
5x° = 5(10) = 50°
2x ° = 2(10) = 20°
110 + 7x = 180
7x = 180 - 110
7x = 70
x = 10 answer//
then
5x° = 5(10) = 50°
2x ° = 2(10) = 20°
收錄日期: 2021-04-18 18:26:17
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