container of water at 0◦C.
How much water freezes onto the ice? The
specific heat of ice is 0.5 cal/g ·
◦ C and its heat
of fusion of is 80 cal/g.
Answer in units of g.
A 80 g ice cube at −17◦C is dropped into a?
2020-04-07 12:41 pm
回答 (4)
2020-04-07 11:50 pm
✔ 最佳答案
mass of water frozen m = MCdT / Lice ie., m = 80x0.5x17/80 = 8.5 gm.
2020-04-07 1:21 pm
Heat gained when 80 g ice from -17°C to 0°C
= m c ΔT
= (80 g) × (0.5 cal/g°C) × (17 °C)
= 680 cal …… [1]
Heat lost when m g of water freezes
= m Lf
= (m g) × (80 cal/g)
= 80m cal …… [2]
[2] = [1]
80m = 680
m = 8.5
Mass of water freezes onto the ice = 8.5 g
= m c ΔT
= (80 g) × (0.5 cal/g°C) × (17 °C)
= 680 cal …… [1]
Heat lost when m g of water freezes
= m Lf
= (m g) × (80 cal/g)
= 80m cal …… [2]
[2] = [1]
80m = 680
m = 8.5
Mass of water freezes onto the ice = 8.5 g
2020-04-07 1:00 pm
energy = mass of ice * specific heat of ice * temperature change
energy = mass of water * heat of fusion of water.
About 8 g.
energy = mass of water * heat of fusion of water.
About 8 g.
2020-04-07 12:52 pm
do your own homework, billy
收錄日期: 2021-04-18 18:25:48
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