If triplicate absorbance readings of 0.419, 0.430, and 0.416 are recorded, what is the average %T for this solution?

2020-04-07 1:26 am

Adding them all up and dividing by 3 didn't work.

回答 (1)

2020-04-07 1:30 am

Reject the reading of 0.430 because of the great deviations from the other two readings.

Average %T for the solution
= (0.419 + 0.416) / 2
= 0.418

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