If triplicate absorbance readings of 0.419, 0.430, and 0.416 are recorded, what is the average %T for this solution?
Adding them all up and dividing by 3 didn't work.
回答 (1)
Reject the reading of 0.430 because of the great deviations from the other two readings.
Average %T for the solution
= (0.419 + 0.416) / 2
= 0.418
收錄日期: 2021-05-01 22:34:39
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