The density of a gas is 1.48 g/L at a temperature of 24 ∘C and a pressure of 0.784 atm . Calculate the molar mass of the gas.?
2020-04-06 10:01 am
Express the molar mass to three significant figures and include the appropriate units.
回答 (2)
2020-04-06 10:46 am
✔ 最佳答案
Density, d = 1.48 g/LTemperature, T = (273 + 24) K = 297 K
Pressure, P = 0.784 atm
Gas constant, R = 0.08206 L•atm/(mol•K)
Molar mass, M = ? g/mol
PV = nRT and n = m/M
Hence, PV = (m/M)RT
M = (m/V)RT/P
Since, d = m/V, M = dRT/P
Molar mass, M = 1.48 × 0.08206 × 297 / 0.784 g/mol = 46.0 g/mol
2020-04-06 10:42 am
1.48 g/L at a temperature of 24 ∘C and a pressure of 0.784 atm . ....... Separate density into 2 parts .. 1.48g = mass ... 1L = volume
PV = nRT ..... n = (PV)/(RT)
n = (0.784 X 1) / (0.0821 X 297)
n = 0.03215 moles
molar mass = 1.48g / 0.03215 moles
= 46.0 g/mol
PV = nRT ..... n = (PV)/(RT)
n = (0.784 X 1) / (0.0821 X 297)
n = 0.03215 moles
molar mass = 1.48g / 0.03215 moles
= 46.0 g/mol
收錄日期: 2021-04-18 18:31:45
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