What is the temperature of 0.62 mol of gas at a pressure of 1.5 atm and a volume of 11.7 L ?

[匿名]

2020-04-06 9:58 am

Express the temperature in kelvins to two significant figures.

回答 (2)

戇戇居士

2020-04-06 10:51 am

✔ 最佳答案

PV = nRT
Hence, T = PV/(nR)

Temperature, T = 1.5 × 11.7 / (0.62 × 0.08206) K = 340 K

👍 4 👎 0

david

2020-04-06 10:50 am

  PV = nRT
  T = (PV)/(nR) = (1.5 X 11.7)/(0.62 X 0.0821)
   T = 344.78 K  <<  round as appropriate

👍 1 👎 0

收錄日期: 2021-04-18 18:25:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200406015846AAXXOMa

檢視 Wayback Machine 備份