What is the temperature of 0.62 mol of gas at a pressure of 1.5 atm and a volume of 11.7 L ?
回答 (2)
2020-04-06 10:51 am
✔ 最佳答案
PV = nRTHence, T = PV/(nR)
Temperature, T = 1.5 × 11.7 / (0.62 × 0.08206) K = 340 K
2020-04-06 10:50 am
PV = nRT
T = (PV)/(nR) = (1.5 X 11.7)/(0.62 X 0.0821)
T = 344.78 K << round as appropriate
T = (PV)/(nR) = (1.5 X 11.7)/(0.62 X 0.0821)
T = 344.78 K << round as appropriate
收錄日期: 2021-04-18 18:25:34
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