The Ksp of iron (II) carbonate is 3.5E-7. How many liters of a saturated solution of iron(II) carbonate will contain 0.088 grams of iron(II)?

2020-04-03 12:24 pm
Help!!!

Give your answer with at least one decimal point.Data: Fe 55.8 g/mol; C 12 g/mol; O 16 g/mol

回答 (1)

2020-04-03 12:49 pm
_____FeCO₃(s) ⇌ Fe²⁺(aq) + CO₃²⁻(aq) ___ Ksp = 3.5 × 10⁻⁷
Equilibrium: ______ s M _____ s M

At equilibrium:
Ksp = [Fe²⁺] [CO₃²⁻]
3.5 × 10⁻⁷ = s²
s = √(3.5 × 10⁻⁷) = 5.92 × 10⁻⁴

[Fe²⁺] = (5.92 × 10⁻⁴ mol/L) × (55.8 g/mol) = 0.0330 g/L
Volume of the solution = (0.088 g) / (0.0330 g/L) = 2.67 L


收錄日期: 2021-04-18 18:26:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200403042437AAjLZuN

檢視 Wayback Machine 備份