CHEMISTRY HELP?

Heat given off when burning 1.764 g of ethanol
= Heat gained by the calimeter
= (34.65 kJ/K) × [(295.93 - 294.42) K]
= 52.32 kJ

Molar mass of C₂H₆O
= (12.0×2 + 1.0×6 + 16.0) g/mol
= 46.0 g/mol

Moles of 1.764 g of C₂H₆O
= (1.764 g) / (46.0 g/mol)
= 0.03835 mol

As heat is given off, the reaction is exothermic, i.e. ΔH < 0
ΔH for the combustion of C₂H₆O
= -(52.32 kJ) / (0.03835 mol)
= -1364 kJ/mol

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