find the following angles to the nearest tenth of a degree
sin theta= .1234
cit theta= 2.176
find the angles ?
2020-03-23 2:02 pm
回答 (2)
2020-03-23 2:17 pm
Suppose that it is "cot" instead of "cit".
sinθ = 0.1234
θ = sin⁻¹0.1234
θ = 7.1° for 0° ≤ θ ≤ 90°
OR: θ = 180n° + (-1)ⁿ(7.1°) for n = 0, 1, 2, 3, ….
cotθ = 2.176
tanθ = 1/2.176
θ = tan⁻¹(1/2.176)
θ = for 24.7° 0° ≤ θ ≤ 90°
OR: θ = 180n° + 24.7° for n = 0, 1, 2, 3, ….
sinθ = 0.1234
θ = sin⁻¹0.1234
θ = 7.1° for 0° ≤ θ ≤ 90°
OR: θ = 180n° + (-1)ⁿ(7.1°) for n = 0, 1, 2, 3, ….
cotθ = 2.176
tanθ = 1/2.176
θ = tan⁻¹(1/2.176)
θ = for 24.7° 0° ≤ θ ≤ 90°
OR: θ = 180n° + 24.7° for n = 0, 1, 2, 3, ….
2020-03-23 2:13 pm
hint : arcsin and arccot
收錄日期: 2021-04-18 18:25:36
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