Physics help?
2020-02-28 11:27 pm
A proton with a mass of 1.67x10^(-27) kg is released from rest from the positive plate in a parallel plate apparatus. If the voltage applied to the plates is 350 V, determine the velocity of the proton just before it hits the negative plate.
回答 (3)
2020-02-29 1:15 am
✔ 最佳答案
Potential is (potential) energy per unit charge, so the proton trades its PE forKE = 350J/C * 1.6E-19C = 5.6E-17 J
so
5.6E-17 J = ½mv² = ½ * 1.67E-27kg * v²
means that
v = 2.59E5 m/s
2020-02-28 11:45 pm
velocity of proton v= sq.root ( 2Ve/ m ) = sq.root ( 2x350x1.6x10’-19 / 1.67x10’-27 ) = 2.6x105 m/sec.
2020-02-28 11:28 pm
It will be fast, very fast, ludicrous fast!
收錄日期: 2021-04-11 23:04:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200228152715AAVhPDy