已知f(x)=x^3+2x^2-x+3,g(x-1)=f(x)及h(x+1)=g(x+3),則f(x)+xh(x)除以x+1之餘?
回答 (1)
2020-02-18 9:32 am
✔ 最佳答案
f(x)=x^3+2x^2-x+3,g(x-1)=f(x) ==> g(x) = f(x+1)
h(x+1)=g(x+3) ==> h(x) = g(x+2) = f(x+3)
∴ f(x)+xh(x) = f(x)+x．f(x+3)
一多項式 p(x) 除以 x-a 的餘式是 p(a).
故 f(x) + x f(x+3) 除以 x+1 其餘式為
f(-1) + (-1)f(-1+3) = f(-1)-f(2)
= (-1+2+1+3) - (8+8-2+3)
= 5 - 17 = -12
收錄日期: 2021-05-04 00:38:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200218005019AA1TAi0