Relation between refractive index & critical angel??
回答 (3)
2019-12-31 12:52 pm
When light rays travel from a medium of higher optical density (with refractive index n₁) to a medium of lower optical density (with refractive index n₂), the critical angle, C, is given by:
sinC = n₂/n₁
Generally, the medium of lower optical density is water which has a refractive index very close to 1. Then,
sinC = 1/n₁
sinC = n₂/n₁
Generally, the medium of lower optical density is water which has a refractive index very close to 1. Then,
sinC = 1/n₁
2019-12-31 2:02 pm
Because Snell's law is n1 sin(theta1)= n2 sin( theta 2) and because sin( angle) cannot ever be greater than 1,
you get sin( theta1) = n2/n1 ( if n2<n1)
It is impossible to get a critical angle of incidence if n2>n1
you get sin( theta1) = n2/n1 ( if n2<n1)
It is impossible to get a critical angle of incidence if n2>n1
2019-12-31 12:50 pm
Critical angle = arcsin(refractive index a / refractive index b)
收錄日期: 2021-04-24 07:44:15
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https://hk.answers.yahoo.com/question/index?qid=20191231044118AAnnoF3