Maths problem, how to do, thanks?
回答 (1)
2019-12-28 10:18 pm
✔ 最佳答案
(a)3(x - 3)(x - 2) + a = 0
3(x² - 5x + 6) + a = 0
3x² - 15x + 18 + a = 0
a = -3x² + 15x - 18
(b)
y = 3(x - 3)(x - 2) + a
3(x - 3)(x - 2) + a = 0
a = -3x² + 15x - 18
a = (-15 ± √(15² - 4 × (-3) × (-18))) ÷ (2 × (-3))
a = 2 or a = 3
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