Based on the difference in electronegativities of the elements, which of the bonds would be classified as a nonpolar covalent bond?

2019-12-04 9:10 pm
  C - H
  H - F
  N - F
  H - O
  B - Cl

回答 (1)

2019-12-04 9:58 pm
Refer to: https://en.wikipedia.org/wiki/Electronegativity
Electronegativity (EN) by Pauline scale:
C = 2.55, H = 2.20, N =3.04, F = 3.98, O = 3.44, B = 2.04, Cl = 3.16

Difference in EN between the two bonding atoms:
in C-H bond = 2.55 - 2.20 = 0.32
in H-F bond = 3.98 - 2.20 = 1.78
in N-F bond = 3.98 - 3.04 = 0.94

in H-O bond = 3.44 - 2.20 = 1.24

in B-Cl bond = 3.16 - 2.04 = 1.12


The smaller the difference in EN between the two bonding atoms, the lower is the polarity of the bond is.

C-H bond has the smallest differernce EN between the two bonding atoms, and thus its polarity is the lowest.

Hence, C-H bond can be classified as nonpolar covalent bond.


The answer: C-H


收錄日期: 2021-04-18 18:26:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20191204131047AA9LszT

檢視 Wayback Machine 備份