(m-n)(m-n) + n(n-m)?
回答 (1)
2019-11-27 5:10 pm
(m-n)(m-n) + n(n-m) = (m-n)(m-n) - n(m-n) = (m-n)[(m-n)-n] = (m-n)(m-2n) ..ans
收錄日期: 2021-04-18 18:33:17
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https://hk.answers.yahoo.com/question/index?qid=20191127062354AADNM7M