calculate the molarity of the solutions made by mixing 175 ml of 3.0 m HCl with the following: 250 ml of H2O?
回答 (2)
2019-11-10 5:01 am
Dilution question ....
Since you are asking about molarity and since students often get molarity (M) and molality (m) confused, we will assume you meant a 3.0 molar (3.0M) solution. Assume the volumes of the solutions are additive.
175 mL x (3.0 M HCl / 1L) / 425 mL = 1.2M HCl ............. after rounding 1.235M to two significant digits
Since you are asking about molarity and since students often get molarity (M) and molality (m) confused, we will assume you meant a 3.0 molar (3.0M) solution. Assume the volumes of the solutions are additive.
175 mL x (3.0 M HCl / 1L) / 425 mL = 1.2M HCl ............. after rounding 1.235M to two significant digits
2019-11-10 3:41 am
total volume == 175 + 250 = 425 mL
use the dilution formula
M1V1 = M2V2
(3.0)(175) = M2(425)
M2 = (3.0)(175) / (425) = 1.4353M round for sig figs ... you can do that, right?
use the dilution formula
M1V1 = M2V2
(3.0)(175) = M2(425)
M2 = (3.0)(175) / (425) = 1.4353M round for sig figs ... you can do that, right?
收錄日期: 2021-04-18 18:26:38
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