Does white light have more energy than violet light?

2019-11-08 9:03 am
I was wondering since white light contains all wavelengths, but I hear violet is the most energetic wavelength in the visible spectrum, I know that violet has more than red,
yellow, blue, etc, but what about white light wouldn’t that be the most energetic color of the visible spectrum. Thank you to all who answer!

回答 (4)

2019-11-08 6:28 pm
✔ 最佳答案
White light is a bundle of light rays of all frequencies. Like Zaadu in India. Violet light is like one stick in it. So you need many more violet rays to make it equal to the energy of white light. If the white light contains 100 rays then 100 violet rays more powerful than white light.
2019-11-08 9:09 am
A violet PHOTON has more energy than other photons.  It is not true that violet LIGHT has more energy because it depends on the number of photons.
In white light there are many different photons of differing energies each.
But none of the photons can have MORE energy than the violet photon.
Many have less.  So the AVERAGE energy per photon is less.The total energy depends entirely on the number of these photons present.
2019-11-08 12:02 pm
No. White light is a mixture of all colors, including violet light. Violet light has the highest energy because it has the highest frequencies and short wavelengths. Red and infrared have the lowest energy because the have longer frequencies and wavelengths..I am including shortwave infrared because some people CAN see infrared light.

E = hv where E = energy, h = the Planck constant and v, which should be a Greek nu, is frequency.

You seem to be mixing up energy with intensity and luminosity and power. Those are all different things.
2019-11-08 10:05 am
Basically, white is not a color of the spectrum. It is what you get when you mix together lots of colors in the spectrum.

the total energy of light would be the sum of the individual photons.  "white" light is a mixture of many colors so consists of a very large number of photons, or it won't appear as white. Many photons will naturally most likely amount to more total energy than a single photon of some specific wavelength.  If you were to have the same number of photons in the white light as in a specific color of light, then you could compare, but otherwise, you are not really comparing color, you are comparing number of photons (intensity of the light). Brightness of the light is really the measure of total energy, mostly, rather than anything to do with the energy of individual packets of light (photon).

Presumably, if white light were truly white and had an even distribution of photons across the visible wavelength, then that light would have the same energy as the same amount of photons of a middle color, about. White light often is actually dominated by a particular wavelength, though, which gives it a tinge of that color, so you can have a bluish white light or a yellowish white light.

Even when we discuss colors of light, we really are discussing light of unique and specific wavelength.  Most color that we see does not comply with that idea, unless you have done something to the light to force the separation by wavelength.

E=h/wavelength, when dealing with one photon, the smallest unit that light can exist as.

You are sort of like asking, given that each element has a different weight, would a rock be heavier or lighter than one of those elements?  A rock is a big slew of elements so you cannot make that comparison.  You can break down the elements in the rock and how many atoms of each are present, and compare, just as you can do the same with white light. But it really doesn't mean much without being very specific.


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