急需!跪求極限值QQ...?

2019-10-29 11:13 am
解答:2x-2
我算出來的是∆x-2

回答 (1)

2019-10-29 12:35 pm
✔ 最佳答案
(題目印漏了Δ)
lim(Δx→0) ((x+Δx)² - 2(x+Δx) + 1 - (x²-2x+1))/Δx
= lim(Δx→0) ((x+Δx -1)² - (x-1)²)/Δx
= lim(Δx→0) (x+Δx -1 - (x-1))(x+Δx -1 + x-1)/Δx
= lim(Δx→0) Δx (2x+Δx -2)/Δx
= lim(Δx→0) (2x+Δx -2)
= 2x+0 -2
= 2x-2


收錄日期: 2021-04-11 23:02:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20191029031357AAq49Zb

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