國二數學,乘法公式1題?

2019-09-21 3:05 pm
如果a+b=7,請問a^2+2ab+b^2+(a+1)(b+1)等於多少?

回答 (4)

2019-09-22 7:00 am
a^2+2ab+b^2+(a+1)(b+1) = (a+b)^2 +(ab+a+b+1) = 7^2+ab+7+1 = ab+57
2019-10-05 7:55 pm
a+b=7
b=7-a

展開:
  a^2+2ab+b^2+(a+1)(b+1)
=(a+b)^2 +(ab+a+b+1)
= 7^2+ab+7+1
= ab+57
-----接下來可不寫------
=a(7-a)+57
=-a²+7a+57
2019-09-23 8:33 pm
ab+57..........
2019-09-21 5:51 pm
應該要給ab.............


收錄日期: 2021-05-03 15:24:42
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