數學指數問題 對於任意實數X而言,(1/2)的x²-4x+3次方
最大值為?????? 答案是2:不會算式?
回答 (1)
Sol
x^2-4x+3
=(x^2-4x)+3
=(x^2-4x+4)-1
=(x-2)^2-1
(x-2)^2>=0
(x-2)^2-1>=-1
(1/2)^(x^2-4x+3)
=(1/2)^[(x-1)^2-1]
>=(1/2)^(-1)
=(2^-1)^(-1)
=2^1
=2
收錄日期: 2021-04-30 22:49:50
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