1. 3x−5<24/7x+5/7<−3x−5
2. 3x−8≤22/3x+8/3≤6x+4
Convert these into interval notation?
2019-09-05 5:42 am
回答 (1)
2019-09-05 6:07 am
1.
3x - 5 < (24/7)x + (5/7)
3x - (24/7)x < (5/7) + 5
(-3/7)x < 40/7
3x > -40
x > -40/3
(24/7)x + (5/7) < -3x - 5
(24/7)x + 3x < -5 - (5/7)
(45/7)x < -40/7
45x < -40
x < -40/45
x < -8/9
(-40/3, -8/9)
2.
3x - 8 <= (22/3)x + (8/3)
3x - (22/3)x <= (8/3) + 8
(-13/3)x <= 32/3
-13x <= 32
x >= -32/13
(22/3)x + (8/3) <= 6x + 4
(22/3)x - 6x <= 4 - (8/3)
(4/3)x <= 4/3
x <= 1
[-32/13, 1]
3x - 5 < (24/7)x + (5/7)
3x - (24/7)x < (5/7) + 5
(-3/7)x < 40/7
3x > -40
x > -40/3
(24/7)x + (5/7) < -3x - 5
(24/7)x + 3x < -5 - (5/7)
(45/7)x < -40/7
45x < -40
x < -40/45
x < -8/9
(-40/3, -8/9)
2.
3x - 8 <= (22/3)x + (8/3)
3x - (22/3)x <= (8/3) + 8
(-13/3)x <= 32/3
-13x <= 32
x >= -32/13
(22/3)x + (8/3) <= 6x + 4
(22/3)x - 6x <= 4 - (8/3)
(4/3)x <= 4/3
x <= 1
[-32/13, 1]
收錄日期: 2021-05-01 22:06:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190904214259AA0A83Y