✔ 最佳答案
From △BAE :
∵AB=AE, ∴△BAE is an isos.△ => base∠s equal
Let the base∠ be θ
2θ+112° = 180°
∴θ= 34°
So, ∠DCF=∠ABE =θ=34° (corr.∠s equal)
Let AB=DA= 1 unit
Let DF = x,
Then FA= 1-x
From △DCF : tan∠DCF = x/1
∴ x = tan 34°
From △ABF, tan∠ABF = (1-x)/1 = 1-tan 34°
∴∠ABF = 18° Ans. (B)