Maths problem, thankd?

From △BAE :
∵AB=AE, ∴△BAE is an isos.△ => base∠s equal
Let the base∠ be θ
2θ+112° = 180°
∴θ= 34°
So, ∠DCF=∠ABE =θ=34°　(corr.∠s equal)

Let AB=DA= 1 unit
Let DF = x,
Then FA= 1-x
From △DCF : tan∠DCF = x/1
　　　　　　　　∴ x = tan 34°
From △ABF, tan∠ABF = (1-x)/1 = 1-tan 34°
　　　　　　∴∠ABF = 18°　　　　Ans. (B)

The Answer is
D. 26