（x+1）平方×（x-1）平方求解?
回答 (2)
2019-07-25 6:50 pm
Sol
(x+1)^2*(x－1)^2
=[(x+1)(x－1)]^2
=(x^2－1)^2
=x^4－2x^2+1
(x+1)^2*(x－1)^2
=[(x+1)(x－1)]^2
=(x^2－1)^2
=x^4－2x^2+1
2019-07-25 9:31 pm
(x + 1)²(x - 1)²
= (x² - 1)²
= x⁴ - 2x² + 1 #
= (x² - 1)²
= x⁴ - 2x² + 1 #
收錄日期: 2021-04-30 22:49:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190725092637AAe7xRP