Point P(-5,2) lies on the graph of y=1/3f(-(x+1)). Determine the original point on y=f(x).?
回答 (1)
2019-07-07 11:19 pm
y=f(-x-1)/3
=>
2=f(4)/3
=>
f(4)=6
So, (4,6) is on y=f(x).
=>
2=f(4)/3
=>
f(4)=6
So, (4,6) is on y=f(x).
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