電阻4Ω與電感抗j4Ω並聯，等效阻抗Z為多少？ (A)8＋J8Ω (B)2＋J2Ω (C)4＋J4Ω (D)J64Ω。?
回答 (2)
2019-07-06 10:12 pm
Z=Z1*Z2/(Z1+Z2)
=4*j4/(4+j4)
=j4/(1+j)
=j4*(1-j)/((1+j)(1-j))
=(j4+4)/(1+1)
=2+j2 Ω
=4*j4/(4+j4)
=j4/(1+j)
=j4*(1-j)/((1+j)(1-j))
=(j4+4)/(1+1)
=2+j2 Ω
2019-07-05 12:38 pm
電阻與電感並聯等效阻抗
Z=R+jL= 4＋J4Ω
(C)4＋J4Ω
Z=R+jL= 4＋J4Ω
(C)4＋J4Ω
收錄日期: 2021-05-04 01:06:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190704180546AAi90bB