lnx + c = ln2x what is c?

The way I looked at this was to split up the ln(2x) into the sum of two logs:

ln(x) + c = ln(2x)
ln(x) + c = ln(2) + ln(x)

Since the log of a product is the same as the sum of the logs.

Now we can subtract ln(x) from both sides:

c = ln(2)

lnx+c = ln(2x) = ln2+lnx
c = ln2

Ln(x )+ c = ln(2x)

c = ln(2)

ln(x) + c = ln(2x) =>
c = ln(2)