By taking limit of n tends to infinity [sin(1/n)]/(i/n)=-i. I can't get -i. Anybody can help. This is under complex ananlysis.?

Remember that sin(k) / k goes to 1 as k goes to 0

1/n = k
lim n->inf 1/n = k
0 = k

Therefore, we're taking the limit of k as k goes to 0

lim n->inf sin(1/n) / (i/n) =>
lim n->inf (1/i) * sin(1/n) / (1/n) =>
lim k->0 (1/i) * sin(k) / k =>
(1/i) * 1 =>
1/i =>
1 * i^3 / (i * i^3) =>
i^3 / i^4 =>
i^2 * i / 1 =>
-1 * i =>
-i