微積分問題，求解~~?
回答 (1)
2019-04-30 2:06 pm
✔ 最佳答案
SolA=∫(0 to 1)_x^2ln(x^3+1)dx
Set y=x^3+1
3x^2dx=dy
3A=∫(0 to 1)_3x^2ln(x^3+1)dx
=∫(1 to 2)_lnydy
Set u=lny，dv=dy
du=(1/y)dy，v=y
3A=ylny｜(1 to 2)－∫(1 to 2)_y*(1/y)dy
=(2ln2－1ln1)- ∫(1 to 2)_dy
=2ln2－1
A=(2ln2－1)/2
收錄日期: 2021-04-30 22:47:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190430035917AAsCvn1