Maths: Polynomial, how to do, thanks?
回答 (1)
2019-04-09 5:38 am
✔ 最佳答案
a/(6x+4)－b/(3x+4)=12/(9x^2+18x+8)(18x^2+36x+16)*[ a/(6x+4)－b/(3x+4)]=(18x^2+36x+16)*[12/(9x^2+18x+8)]
a(3x+4)－b(6x+4)=24
(3a－6b)x+(4a-4b)=24
3a－6b=0
4a－4b=24
a=2b
4(2b)－4b=24
b=6
a=12
收錄日期: 2021-04-24 07:33:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190408142823AADMieY