energy photon emitted when an electronic a hydrogen atom undergoes transition from n=2, n=3?
回答 (1)
2019-03-31 12:03 am
Rdyberg formula: 1/λ = R [(1/n₁)² - (1/n₂)²]
and E = hc/λ
Hence, E = h c R [(1/n₁)² - (1/n₂)²]
Energy, E = (6.626 × 10⁻³⁴ J s) × (3.00 × 10⁸ m/s) × (1.097 × 10⁷ /m) × [(1/2)² - (1/3)²] = 3.03 × 10⁻¹⁹ J
and E = hc/λ
Hence, E = h c R [(1/n₁)² - (1/n₂)²]
Energy, E = (6.626 × 10⁻³⁴ J s) × (3.00 × 10⁸ m/s) × (1.097 × 10⁷ /m) × [(1/2)² - (1/3)²] = 3.03 × 10⁻¹⁹ J
收錄日期: 2021-05-02 11:15:58
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https://hk.answers.yahoo.com/question/index?qid=20190330053908AAeOSct