0.25L of a 0.110 M of KOH solution will contain how many grams of the solid KOH?
回答 (1)
Molar mass of KOH = (39.1 + 16.0 + 1.0) g/mol = 56.1 g/mol
Moles of KOH = (0.110 mol/L) × (0.25 L) = 0.0275 mol
Mass of KOH = (0.0275 mol) × (56.1 g/mol) = 1.54 g
收錄日期: 2021-05-01 22:35:18
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190323032939AAigX6D
檢視 Wayback Machine 備份