The standard enthalpy change for the following reaction is 511 kJ at 298 K. SnCl4(l) --> Sn(s, white) + 2 Cl2(g) What is the standard heat o?

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[匿名]

2019-03-22 8:30 am

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The standard enthalpy change for the following reaction is 511 kJ at 298 K. SnCl4(l) --> Sn(s, white) + 2 Cl2(g) What is the standard heat of formation of SnCl4(l)? _____ kJ/mol

回答 (1)

胡雪8°

2019-03-22 9:17 am

✔ 最佳答案

The given thermochemical equation:
SnCl₄(l) → Sn(s, white) + 2 Cl₂(g) …… ΔH° = 511 kJ

Reverse the given thermochemical equation:
Sn(s, white) + 2 Cl₂(g) →SnCl₄(l) ……ΔH° = -511 kJ

The above equation represents that of the standard enthalpy heat of formation of SnCl₄(l).
Hence, ΔHf°[SnCl₄(l)] = -511 kJ/mol

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