For a reaction at 25 ˚C, ∆G˚ = –33.3 kJ and ∆S˚ = –198 J·K–1 . What is the value of ∆H˚?
回答 (1)
2019-03-20 2:17 pm
ΔG° = ΔH° - TΔS°
-33.3 × 1000 J = ΔH° - (273 + 25) (-198 J K⁻¹)
ΔH = -92300 J = -92.3 kJ
-33.3 × 1000 J = ΔH° - (273 + 25) (-198 J K⁻¹)
ΔH = -92300 J = -92.3 kJ
收錄日期: 2021-05-02 11:19:47
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